frustimThe perimeter ofcm Find its volume.ends of a frustum are 48 cm.

1.	frustimThe perimeter ofcm Find its volume.ends of a frustum are 48 cm. and 36 cm. If height of the
Answer» Given height of frustum(h)= 11 cm Let the radius, r1 and radius, r2 be the radii of the circular ends of the frustum and h be its height. perimeter = 36 cm (given) 2 π r1=36r1=36/2π r1=18/π perimeter=48 cm 2 π r2=48 r2= 24/π Volume of Frustum (V)= 1/3 π {(r1)²+ (r2)² + (r1r2)} h V= 1/3 x π x h {(18/π)²+(24/π)²+(18/π x 24/π)} V= 1/3 x π x 11 {324/π²+576/π²+432/π²} V= 1/3 x π x 11x 1/π² (324+576+432) V= 1/3 x π x 11x 1/π² (1332) V= 11/3x 1/π (1332) V= 11/3 x 7/22 (1332) V= (11 x 7× 1332)/ (22 ×3) V= 7 x 222 V= 1554 cm³ Hence, the volume of frustum is 1554 cm³

frustimThe perimeter ofcm Find its volume.ends of a frustum are 48 cm. and 36 cm. If height of the

Answer»

Given height of frustum(h)= 11 cm

Let the radius, r1 and radius, r2 be the radii of the circular ends of the frustum and h be its height.

perimeter = 36 cm (given)

2 π r1=36r1=36/2π

r1=18/π

perimeter=48 cm

2 π r2=48

r2= 24/π

Volume of Frustum (V)= 1/3 π {(r1)²+ (r2)² + (r1r2)} h

V= 1/3 x π x h {(18/π)²+(24/π)²+(18/π x 24/π)}

V= 1/3 x π x 11 {324/π²+576/π²+432/π²}

V= 1/3 x π x 11x 1/π² (324+576+432)

V= 1/3 x π x 11x 1/π² (1332)

V= 11/3x 1/π (1332)

V= 11/3 x 7/22 (1332)

V= (11 x 7× 1332)/ (22 ×3)

V= 7 x 222

V= 1554 cm³

Hence, the volume of frustum is 1554 cm³