Function `x=Asin^(2)omegat+Bcos^(2)omegat+Csinomegat cos omegat` represents simple harmonic motion,A. The motion of particle is `SHM` when `A = B`B. The motion of particle is `SHM` when `A = B` and `C = 0`C. If `B = C/2=-A`, then the amplitude of `SHM` is `B//sqrt(2)`.D. If `A=B =C/2`, then the axis of vibration of `SHM` shifts by a distance `B` towards `+x` axis.

Function `x=Asin^(2)omegat+Bcos^(2)omegat+Csinomegat cos omegat` repre

1.	Function `x=Asin^(2)omegat+Bcos^(2)omegat+Csinomegat cos omegat` represents simple harmonic motion,A. The motion of particle is `SHM` when `A = B`B. The motion of particle is `SHM` when `A = B` and `C = 0`C. If `B = C/2=-A`, then the amplitude of `SHM` is `B//sqrt(2)`.D. If `A=B =C/2`, then the axis of vibration of `SHM` shifts by a distance `B` towards `+x` axis.
Answer» Correct Answer - ACD If ` A = B` then `x = A + C sinomegat cosomegat = A + C/2 sin^(2)omegat rArr "SHM"` If `A = B` & `C = 0` then `x = A rArr ` along a straight line. If `B = C/2 = - A` then `x = B cos^(2)omegat + Bsin2omegat rArr "amplitude" = Bsqrt(2)` If `A = B= C/2` then `x = B + Bsin2omegat rArr` Axis of vibration of SHM shifts by a distance B towards `+ x-` axis.

Discussion

No Comment Found

Related InterviewSolutions

The probaility that a certaun radioactive atom would get disintefrated in a time equal to the mean life fo the radioactive sample isA. `0.37`B. `0.63`C. `0.50`D. `0.67`
If `N_(t) = N_(o)e^(lambdat)` then number of disintefrated atoms between `t_(1)` to `t_(2) (t_(2) gt t_(1))` will ve :-A. `N_(o)[e^(lambdat_(2))-e^(lambdat_(3))]`B. `N_(o)[-e^(lambdat_(2)) - e^(-lambdat_(1))]`C. `N_(o)[e^(-lambdat_(1)) - e^(-lambdat_(2))]`D. None of these
Identify the correct variation of potential energy `U` as a function of displacement `x` from mean position (or `x^(2)`) of a harmonic oscillator (`U` at mean position `= 0`)A. B. C. D. None of these
The variation of potential energy of harmonic oscillator is as shown in figure. The spring constant is A. `1 xx 10^(2)Nm^(-1)`B. `1.5 xx 10^(2) Nm^(-1)`C. `2 xx 10^(2)Nm^(-1)`D. `3 xx 10^(2)Nm^(-1)`
The variation of potential energy of harmonic oscillator is as shown in figure. The spring constant is A. ` 1 xx10^(2) N/m `B. 150N/mC. `667 xx 10^(2) N//m`D. `3 xx 10^(2)` N/m
A body performs S.H.M. Its kinetic energy K varies with time t as indicated by graphA. B. C. D.
A ball of mass `m kg` hangs from a spring of spring constant `k`. The ball oscillates with a period of `T` seconds if the ball is removed, the spring is shortened(`w.r.t.` length in mean position) byA. `(gT^(2))/((2pi)^(2))` metreB. `(3T^(2)g)/((2pi)^(2))` metreC. `(Tm)/(k,)` metreD. `(Tk)/(m)` metre
A smooth inclined plane having angle of inclination `30^(@)` with horizontal has a mass `2.5 kg` held by a spring which is fixed at the upper end as hwon in figure. If the mass is taken `2.5 cm` up along the surface of the inclined plane, the tension in the soring reduces to zero. If the mass is then released, the angular frequency of oscillation in radian per second is A. `0.707`B. `7.07`C. `1.414`D. `14.14`
A smooth inclined plane having angle of inclination `30^(@)` with horizontal has a mass `2.5 kg` held by a spring which is fixed at the upper end as hwon in figure. If the mass is taken `2.5 cm` up along the surface of the inclined plane, the tension in the soring reduces to zero. If the mass is then released, the angular frequency of oscillation in radian per second is A. `0.707`B. `7.07`C. `1.414`D. `14.14`
A particle executes simple harmonic motion under the restoring force provided by a spring. The time period is T. If the spring is divided in two equal parts and one part isused to continue the simple harmonic motion, the time period willA. remain`T`B. becomes `2T`C. become `T//2`D. become `T//sqrt(2)`

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment