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G , एक समबाहु त्रिभूज ABC का केंद्रक है | तदनुसार यदि AB = 9 से. मी हो , तो AG किसके बराबर होगा ?A. `3sqrt(3)cm `B. 3 cmC. `(3sqrt(3))/(sqrt(2))cm`D. 6 cm |
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Answer» Correct Answer - A G is centroid which divides medians in the ratio of `2:1` In case of equilateral triangle length of median `=(sqrt(3)a)/2` `AG = sqrt(3)/2 xx 9 xx 2/3 = 3sqrt(3)` |
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