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Gap between Bohr's atomic radii of he +ve of 3rd orbit and 5 orbit will be.​

Answer»

HEYA,

BOHR's ORBIT for a orbit n of ELEMENT having atomic number z is GIVEN by :- ( in angstrom)

\frac{0.529 {n}^{2} }{z}

For He, z = 2,

for n = 3

\frac{.529 \times 9}{2} \\ \\ for \: n = 5 \\ \\ \frac{.529 \times 25}{2} \\ \\ hence \: gap = \frac{0.529( \frac{25}{2} - \frac{9}{2}) }{} \\ \\ = 0.529 \times 8 \\ = 4.232 \: angstrom

Regards

Kshitij


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