Gaseous benzene reacts with hydrogen gas in presence of a nickel catalyst to form gaseous cyclohenane according to the reaction C_(6) H_(6) (g) + 3H_(2) (g) rarr C_(6) H_(12) (g) A mixture of C_(6)H_(6) and excess H_(2)has a pressure of 60 mm of Hg in an unknown volume. After the gas had been passed over a nickel catalyst and all the benzene converted to cyclohexane, the pressure of the gas was 30 mm of Hg in the same volume at the same temperature. The fraction of C_(6)H_(6) (by volume) present in the original volume is

Gaseous benzene reacts with hydrogen gas in presence of a nickel catal

1.	Gaseous benzene reacts with hydrogen gas in presence of a nickel catalyst to form gaseous cyclohenane according to the reaction C_(6) H_(6) (g) + 3H_(2) (g) rarr C_(6) H_(12) (g) A mixture of C_(6)H_(6) and excess H_(2)has a pressure of 60 mm of Hg in an unknown volume. After the gas had been passed over a nickel catalyst and all the benzene converted to cyclohexane, the pressure of the gas was 30 mm of Hg in the same volume at the same temperature. The fraction of C_(6)H_(6) (by volume) present in the original volume is
Answer» `1//3` `1//4` `1//5` `1//6` SOLUTION :`C_(6)H_(6) (g) + 3H_(2) (g) rarr C_(6) H_(12) (g)` Initial pressure = 60 mm Final pressure = 30 mm since `p PROP n` `:.` Initial pressure of 60 mm is because of 4 moles and hence pressure due to one mole = 15 mm Now if `x` is fraction of `C_(6)H_(6)` which combines then for the REACTION `{:(C_(6)H_(6),+,3H_(2) rarr,C_(6) H_(12)),(15 - x,,45 - 3X,x):}`