1.

Geo-stationary satellite is at …... height from surface of Earth.

Answer»

16000 km
22000 km
28000 km
36000 km

Solution :`implies` The time PERIOD of geostationary satellite is its period of RATATION of the same as that of the earth
`:. (GMm)/r^2 + momega^2 r =0`
`r^3 = (GM)/((2PI)^2) xx T^2`
`G = 6.67 xx 10^(-11) Nm^(2) kg^(-2)`
mass of earth `M = 5.8 xx 10^(24) kg`
Time period `T = 24 xx 3600` second and
Radius of earth `R_e = 6400 km `
`r = 42260 km `
`H = r- R_e = 42260 - 6400`
`= 35860 km ~~ 3600 km`


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