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Geo-stationary satellite is at …... height from surface of Earth. |
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Answer» 16000 km `:. (GMm)/r^2 + momega^2 r =0` `r^3 = (GM)/((2PI)^2) xx T^2` `G = 6.67 xx 10^(-11) Nm^(2) kg^(-2)` mass of earth `M = 5.8 xx 10^(24) kg` Time period `T = 24 xx 3600` second and Radius of earth `R_e = 6400 km ` `r = 42260 km ` `H = r- R_e = 42260 - 6400` `= 35860 km ~~ 3600 km` |
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