Saved Bookmarks
| 1. |
Get an expression for stopping distance of a vehicle in terms of intial velocity v_(a) and deceleration "a"… |
|
Answer» Solution :Let s be the distance travelled by a VEHICLE before it stops USING `v^(2)-u^(2)=2as,` `0_(0)^(2)=-2as` `s=(v_(0)^(2))/(2a)` The stopping distance is directily proportional to `v_(0)^(2)`. By DOUBLING intial velocity it increase stopping distance by 4 TIMES. Provided deceleration is kept as constant. |
|