1.

Get an expression for stopping distance of a vehicle in terms of intial velocity v_(a) and deceleration "a"…

Answer»

Solution :Let s be the distance travelled by a VEHICLE before it stops
USING `v^(2)-u^(2)=2as,`
`0_(0)^(2)=-2as`
`s=(v_(0)^(2))/(2a)`
The stopping distance is directily proportional to `v_(0)^(2)`. By DOUBLING intial velocity it increase stopping distance by 4 TIMES. Provided deceleration is kept as constant.


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