GHD respectively, prove that GL || HM. In the even figure, ABCD and a transversal EF cuts them at G and HI GZ and HM are the bisectors of the alternate angles XAGH and

GHD respectively, prove that GL || HM. In the even figure, ABCD and

1.	GHD respectively, prove that GL \|\| HM. In the even figure, ABCD and a transversal EF cuts them at G and HI GZ and HM are the bisectors of the alternate angles XAGH and
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