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Give calculation of gas constant R for unit of bar Lit mol^(-1)K^(-1) in ideal gas equation. |
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Answer» <P> Solution :R = 0.08314 BAR L `mol^(-1)K^(-1)`.pV = nRT and `R=(pV)/(NT)` `R=(("1 bar")(22.71L))/((1mol)(273.15 K))` where, p = 1 bar V = 22.71 L T = 273.15 K n = 1 mole. R = 0.083141 bar L `mol^(-1)K^(-1)` `R=8.0314x10^(-2)` bar L `mol^(-1)K^(-1)`. |
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