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Give electron configuration, bond order and magnetic property, energy diagram in MO for Helium (He_(2)) molecule. OR (He_(2))molecule is not possible . |
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Answer» Solution :He (Z = 2), So, Total electron in `He_(2)` = 4 Electron CONFIGURATION in MO`He_(2) : (sigma_(1s))^(2) (sigma_(1s)^(**))^(2)` All electron are PAIRED in `He_(2)`, so it is diamagnetic , Bond order = `(1)/(2) (N_(b) - N_(a)) = (1)/(2) (2 - 2) = 0` Bond order in `He_(2)` is zero. So it is unstable and does not exist. Mo energy diagram of `He_(2)` is as under.
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