1.

Give electron configuration, bond order and magnetic property, energy diagram in MO for Helium (He_(2)) molecule. OR (He_(2))molecule is not possible .

Answer»

Solution :He (Z = 2), So, Total electron in `He_(2)` = 4 Electron CONFIGURATION in MO`He_(2) : (sigma_(1s))^(2) (sigma_(1s)^(**))^(2)`
All electron are PAIRED in `He_(2)`, so it is diamagnetic ,
Bond order = `(1)/(2) (N_(b) - N_(a)) = (1)/(2) (2 - 2) = 0`
Bond order in `He_(2)` is zero. So it is unstable and does not exist.
Mo energy diagram of `He_(2)` is as under.


Discussion

No Comment Found