Give electron configuration, bond order, magnetic property and energy diagram for berilium (Be_(2)) molecule and writ about itexistence.

Give electron configuration, bond order, magnetic property and energy

1.	Give electron configuration, bond order, magnetic property and energy diagram for berilium (Be_(2)) molecule and writ about itexistence.
Answer» Solution :Be (Z = 4) So, TOTAL electron in `Be_(2) ` = 8 Electron configuration in MO for `Be_(2)` : KK `(sigma 2s)^(2) (sigma^() 2s)^(2) "OR " (sigma 1S)^(2) (sigma^() 1s)^(2) (sigma 2s )^(2) (sigma^(**) 2s)^(2)` Magnetic Property : All electrons are paired . So, diamagnetic Bond ORDER BO `= (1)/(2) (N_(b)- N_(a) ) = (1)/(2) (2 - 2) = 0 " OR " ` BO = `(1)/(2) (N_(b) - N_(a))= (1)/(2) ( 4 - 4) = 0 ` Bond order is zero, So, `Be_(2)` is unstable and does not exist. Energy diagram for `Be_(2)` molecule is as under.