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Give electron configuration, bond order magnetic property and energy diagram for Lithium (Li_(2)) molecule. |
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Answer» SOLUTION :Li (Z = 3), So, Total electron in `Li_(2)` = 16 Electron configuration in MO for `Li_(2)`: `(SIGMA 1s)^(2) (sigma^(**) 1s)^(2) (sigma 2s)^(2) (sigma^(**) 2s)^(0) "ORKK" (sigma 2s)^(2) ` Magnetic Property : All electrons are PAIRED. So, it should be diamagnetic. where , `N_(b) = 4, N_(a) = 2 ` Bond order `= (1)/(2) (N_(b) - N_(a))` = `(1)/(2) (4- 2 ) = 1 ` So, single bond and `Li_(2) ` is STABLE Note : KK means `[He_(2)] = (sigma 1s )^(2) (sigma^(**) 1s )^(2)` Energy diagram for `Li_(2)` molecule is as under.
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