Saved Bookmarks
| 1. |
Give electron configuration, Magnetic property, bond order and energy diagram for carbon (C_(2)). |
|
Answer» Solution :`C_(2) (z =6) 1s^(2) 2S^(2) 2p^(2)`, So TOTAL electron in `C_(2)` = 12 Electron configuration in MO for `C_(2)` : `(sigma 1s)^(2) (sigma^(**) 1s)^(2) (sigma 2s )^(2) (sigma^(**) 2s)^(2) (pi 2p_(x))^(2) (pi 2p_(y))^(2)` OR KK `(sigma 2s)^(2) (sigma^(**) 2s)^(2) (pi 2p_(x))^(2) (pi 2p_(y))^(^(2) ` Bond order = `(1)/(2) (N_(b) - N_(a)) = (1)/(2) ( 8 - 4) = 2 ` Magnetic Property : All electrons are paired So, diamagnetic Note: In `C_(2)` Molecule, the bond present in double bond are `pi -`bond. Energy DIAGRAM for `C_(2)` molecule : 
|
|