Give electron configuration, magnetic property, bond order and energy diagram for fluorine (F_(2))molecule.

Give electron configuration, magnetic property, bond order and energy

1.	Give electron configuration, magnetic property, bond order and energy diagram for fluorine (F_(2))molecule.
Answer» SOLUTION : `F_(2) (Z = 9) 1s^(2) 2s^(2) 2p^(5)` . In valence CELL 7 ELECTRON and bond structure of `F_(2) ` = 14 ELECTRONS. Electron configuration in MO for `F_(2) `: KK `(sigma_(2s))^(2) (sigma 2p_(z))^(2)(pi 2p_(x))^(2) = (pi 2p_(y))^(2) (pi^()2p_(x))^(2) = (pi^() 2p_(y))^(2)` Bond order = `(1)/(2) (N_(b) - N_(a)) = (1)/(2) ( 10 - 8) = ` So, F - F Single bond Magnetic propoerty : All electrons are paried , So, diamagnetic . Energy diagram for `F_(2)` molecule. :