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Give energy level diagram obtained by over lapping of 2p_(z) orbitals. |
Answer» Solution :By LCAO,` 2p_(z)^(1) - 2p_(z)^(1)` are OVERLEAP and form MO.The energy diagram is under. . Where, AO = Atomic orbitals (here, `2p_(z)`) MO = Molecular orbitals (here, `sigma 2p_(z) sigma^(**) 2p_(z)`) BMO Bonding orbitals (here, `sigma 2p_(z)`) ABMO Antibonding orbitals (here `sigma^(**) 2p_(z)` ) Energy : `(2p_(z)^(1) + 2p_(z)^(1) ) = (sigma 2p_(z) + sigma^(**) 2p_(z))` Energy order : `sigma 2p_(z) lt 2p_(z)^(1) lt sigma^(**) 2p_(z)` NOTE : (i) The electron spin oppostie in both `2p_(z)`like `uarr and darr ` (ii) Two electron in BMO but ABMO is empty. ` because ` The electron filled in first less energy than in high energy. The axia figure of MO, `sigma^(**) 2p_(z) and sigma 2p_(z)` are formed by LCAO of two atom ` 2p_(z)^(1)` are as under figure .  Note: () LCAO in Z-axis, so AO form sigma `(sigma)` types. (ii) BMO `sigma_(2p_(z)) = Psi_(2p_(z)) + Psi_(2p_(z))` ABMO `sigma_(2p_(z))^(**) = Psi_(2p_(z)) - Psi_(2p_(z))` (iii) In `sigma_(2p_(z)) ` BMO electron are symmetrical (iv) In `sigma_(2p_(z))^(*)` ABMO orbital electron COULD is asymmetrical but an INTERNUCLEAR axis. |
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