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Give energy level diagram of molecular orbital obtained by overlapping of 2p_(x)^(1) orbital of two atoms . |
Answer» Solution :Two `2p_(x)` orbital are perpendicular & parallel to internuclear axes overlap and form`pi` MO. The energy level diagram is in given fig.  Where, AO = Atomic ORBITALS `(2p_(x)^(1))` MO = Molecular orbitals `(pi 2p_(x) , pi^(**)2p_(x))` BMO = Bonding orbitals `(sigma 2p_(x))` ABMO = Antibonding orbitals `(sigma^(**)2p_(Z))` Energy order : `pi 2p_(x) lt 2p_(x) lt pi^(**) 2p_(x)` Note : (i) One electron of opposite spin in baoth `2p_(x)` or both ATOM. (ii) BMO energy `lt ` ABMO energy, so according in high energy. to Aufbau and both electron in BMO and ABMO is empty. `because ` the figure ofMO, `(pi 2p_(x)) and (pi^(**) 2p_(x))`which are form by LCAO of `2p_(x)` orbitals of two ATOMS are as under fig.  In `pi` TYPE BMO (+) and (-) waves are below and above of internuclear axis and electron density between two nucleus. In `pi^(**)` type ABMO vertical nodal is located. Electron density is not between two nucleus. (+) and (-) waves are below and above the internuclear axis. |
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