Give one chemical reaction to show that : (i) Tin (II) is a reeducing agent whereas Pb(II) is not. (ii) Tin (II) chloride is a reducing agent.

Give one chemical reaction to show that : (i) Tin (II) is a reeducing

1.	Give one chemical reaction to show that : (i) Tin (II) is a reeducing agent whereas Pb(II) is not. (ii) Tin (II) chloride is a reducing agent.
Answer» Solution :(i) Both tin and lead show two oxidation state of `+2` and `+4` due to inrt pair effect . But the inert pair effect. But the inert pair effectis more prominaent in case of Pb than in Sn. In other words +2, oxidation state of Sn is less stablethan its +4oxidation state. Therefore, `Sn(II)`acts asa reducing agent and GETS cor. erted into more stable `Sn (IV)` by losing two electrons. For example it reduces `Fe^(3+)` to `Fe^(2+)` ions. `2Fe^(+) + Sn^(2+) RARR 2Fe^(2+) + Sn^(4+)` In contrast`+2` oxidation state of Pb is more stable than its +4 oxidation state. In other words, `Pb(II)` does not lose electrons easily and HENCE does not acts as a redusingagent. (ii) Being areducingagent,tin (II) CHLORIDE reeducesmercuric chloride `(HgCl_(2))` to mercurous chloride `(Hg_(2)Cl_(2))` and ferric salt to ferrous salts. `SnCl_(2) + 2HgCl_(2) rarr SnCl_(4) + Hg_(2)Cl_(2)` `SnCl_(2) + 2FeCl_(3) rarr SnCl_(4) + 2 FeCl_(2)`