Give reasons: (i) PbCl_(4) exists but PbI_(4) does not, (ii) SnCl_(2) is solid at room temperature while SnCl_(4) is liquid. (iii) FeI_(3) cannot be prepared.

Give reasons: (i) PbCl_(4) exists but PbI_(4) does not, (ii) SnCl_(2)

1.	Give reasons: (i) PbCl_(4) exists but PbI_(4) does not, (ii) SnCl_(2) is solid at room temperature while SnCl_(4) is liquid. (iii) FeI_(3) cannot be prepared.
Answer» Solution :(i) N/A (II) `Sn^(4+) `having a higher positive charge than `Sn^(2+)` has a greater polarising POWER than `Sn^(2+)` hence the covalency of the corresponding chlorides increases from `SnCl_(2)` to `SnCl_(4)`, which ULTIMATELY RESULTS in decreases in the melting point from `SnCl_(2)` to `SnCl_(4) ` therefore `SnCl_(4)` is a liquid while `SnCl_(2)` in a solid at room temperature. (iii) N/A.