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1. |
Give the decreaes order of`ArSN`reaction of the following with`NaOMe`: |
Answer» a(II)gt(IV)gt(III)gt(I). The leaving group `F` is same,so the`ArSN` reactivity is determined y`EWF(-NO_(2))`group.More the `EWF`,more rapid is the reaction.`EW`power of `(-NO_(2)`at`ogtpgtm`.Although negative charge in arenanion is equally stabilised by `(-NO_(2)`grouo at`o-`and `p-position,-Ipower of (-NO_(2)`group si slighly more at ortho than at para. (IV)gt(III)gt(II)gt(I) More the number of `EWF(-NO_(2))`,faster is the `ArSN`reaction (c ) (I)gt(II)gt(III)gt(IV` The leaving groups are differently .More the`EN`of the leaving group,more is the negative charge srtabilised in the intemediate arenanion,and hence faster is the reaction. (d)`(II)gt(I)gt(III)gt(IV)` The leaving group`Cl`is same.`ArSN`reactivity is determined by`EWG`,More the`EW`power,more is the reactivity .The `EW` power of `-NO_(2)gt-SO_(3)Hgt-C-=Ngt-CHO`. |
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