InterviewSolution
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InterviewSolution
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Give the decreasing order of `((o + p)/(m))` ratio for the nitration of compounds in Problem `11.9`. |
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Answer» Greater the reactivity of `o,p-` directing substiuent, more is the `(( o + p)/(m))` ratio. Similarly, greater the reativity of `m-` directing substituent, less is the `(( o + p)/(m))` ratio. IN problem `11.9`, the reactivity order of `o-,p` directing substituent and of `m-` directing substituent is: `o-,p-` Directing reactivity and `(( o + p)/(m))` ratio order: `underset((IV))(-OR) underset(gt)(gt) underset((I))(-OCOR) underset(gt)(gt) underset((VII))(-CH=CH-COOH) underset(gt)(gt) underset((II))(-CH=CH-NO_(2)) underset(gt)(gt) underset((V))(-R)` m-` directing reactivity order: `underset((VI)) overset(O) overset(||) (-C) -R underset(gt)(gt) underset((III))overset(O)overset(||)(C) - NH_(2)` `(o+p)/(m)` ratio: `(III) gt (IV)` Hence `((o + p)/(m))` ratio order is: `(IV) gt (I) gt (VII) gt (II) gt (V) gt (III) gt (VI)` |
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