1.

Give the decreasing order of `(o+p)/(m)` ratio of the reactions or decreasing order of the reactivity given is problem `11.11`.

Answer» Reactivity order of `SE` reactiion or `((o+p)/(m))` ratio (same explanation as in Problem `11.10`)
`o-, p-` directing reactivity and `((o+p)/(m))` ratio order.
i. `underset((VIII))(-NH-)overset(O)overset(||)(C-) underset(gt)(gt) underset((I))(-R) (-CHMe_(2) underset(gt)(gt) underset((II))(-CMe_(3))) underset(gt)(gt) underset((VII))(-Ar) underset(gt)(gt) underset((III))(I)`
ii. `m-` directing reactivity order:
`underset((V))(-CX_(3)) underset(gt)(gt) underset((VI))(-C) -= N underset(gt)(gt) underset((IV)) overset(O)overset(||)(-C-O-R)`
But `((o+p)/(m))` ratio order of compounds in Problem 11.11 is:
`underset((VIII))(O) underset(gt)(gt) underset((I))(A) underset(gt)(gt) underset((II))(C) underset(gt)(gt) underset((VII))(M) underset(gt)(gt) underset((III))(E) underset(gt)(gt) underset((IV))(G) underset(gt)(gt) underset((VI))(K) underset(gt)(gt) underset((V))(I)`


Discussion

No Comment Found

Related InterviewSolutions