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Give the disproportionation reaction of H_(3)PO_(3). |
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Answer» Solution :`H_(3)PO_(3)` on heating undergoes self-oxidation reduction, (i.e., disproportionation) to form `PH_(3)` in which P is reduced and `H_(3)PO_(4)` in which P is oxidised. `underset("Orthophosphorous acid")overset(+3)(4H_(3)PO_(3))overset(Delta)tounderset("Phosphine")overset(-3)(PH_(3))+underset("Orthophosphoric acid")overset(+5)(3H_(3)PO_(4))` |
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