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Give the electronic configuration of Mn^(2+) and Cr^(3+). |
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Answer» Solution :`Mn(Z=25)""MntoMn^(2+)+2E^(-)` `Mn^(2+)` electronic configuration is `1S^(2)2S^(2)2p^(6)3s^(2)3p^(6)3d^(5)` `Cr(Z=24)""Cr to Cr^(3+)+3e^(-)` `Cr^(3+)` electronic configuration is `1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(3)`. |
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