1.

Give the equilibrium N_2O_4(g) hArr 2NO_(2)(g) wih K_p=0.15 atm at 298 K (a) What is K_p using pressure in torr ? (b) What is K_C using units of moles per litre.

Answer»

Solution :`K_p = ((760 "torr") XX(0.15 atm ))/(1 atm ) = 1.14 xx 10^(2)` torr
`(b) K_p = K_c(RT)^(Delta N)`
`K_(C) = (K_p)/(RT)^(Deltan) = (0.15 atm)/((0.0821 L atmK^(-1) MOL^(-1) xx 298 K)^(2-1))`
`= 6.13 xx 10^(3) "mol" L^(-1)`


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