Saved Bookmarks
| 1. |
Give the expression forworkdoneby thegas. |
|
Answer» Solution :When a gas expands against pressure, it does WORK on the surroundings. The work done in expansion for volume `V_(1)` to `V_(@)` is GIVEN by `W=int_(V_(1))^(V_(2))PDV` If the pressure remains constant during expansion, `"Then"W=P(V_(2)-V_(1))=PDeltaV` If the volume remains constants, then `W=0`. If there is no external pressure, then no work is done. For example, when a gas expands FREELY in vacuum, no work is done by it. |
|