1.

Give the following information, calculate the lattice enthalpy of the sodium chloride lattice: Delta ("atomisation Na") = +107 kJ mol^(-1) "" DeltaH (1^(st) "ionisation Na") = + 496 kJ mol^(-1) Delta H ("bond dissociation " CI_(2)) = +242 kJ mol^(-1) "" Delta (1^(st) "electron affinity CI") =-349 kJ mol^(-1) DeltaH( NaCI) =-411 kJ mol^(-1)

Answer»

SOLUTION :-367 kJ/mol


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