Saved Bookmarks
| 1. |
Give the information about structure of alkene. |
|
Answer» Solution :In alkene, ethene `(C_(2)H_(4))` and propene `(C_(3)H_(6))` has 1 double bond. They do not have isomers. Carbon ATOM 4 or more carbon atom, they do not have any isomers and shows structural isomers. (a) Position isomers : Butene `(C_(4)H_(8))` has 2 position isomers (I) nad (II). `{:(underset((I))underset("But-2-ene")(OVERSET(1)(C)H_(2)=overset(2)(C)H-overset(3)(C)H_(2)-overset(4)(C)H_(3)),|,underset((II))underset("But-2-ene")(overset(1)(C)H_(3)-overset(2)(C)H-overset(3)(C)H-overset(4)(C)H_(3)),):}` Position isomers are in DIFFERENT position of `pi`-bond in (I) and (II). (I) and (II) are SIMPLE chain carbon structure. (b) Alkene chain isomers : Butene `(C_(4)H_(8))` isomers are as follows : e.g., 1 `underset("(I) but-1-ene")(CH_(2)=CH-CH_(2)-CH_(3))` and `underset("(I) Methyl-prop-1-ene")underset(CH_(2)=underset(CH_(3))underset(|)(C)-CH_(3))` (I) and (III) are both chain isomers. e.g, 2 `underset("(II) But-2-ene")(CH_(3)-CH=CH-CH_(3))` and `underset("(III) Methyl prop-1-ene")(CH_(2)-overset(CH_(3))overset(|)(C)-CH_(3))` (II) and (III) are both chain isomers. Chain isomers has same molecular formula. |
|