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Give the IUPAC names for the following (i) CH_(2)=CH-underset(CH_(3))underset(|)CH-CH_(3) (ii) (CH_(3))_(2)CH-CH=CH-CH_(2)-underset(CH_(2)CH_(3))underset(|)underset(H_(3)C-CH-CH)underset(||)(CH_(2) (iii) (iv) CH_(2) = C(CH_(2)CH_(2)CH_(3))_(2) (v) (vi) ( vii)CH_2=CH-CH_2oversetoverset(CH_3)(|)CHCH_3 (viii) CH_(2)=CH-underset(CH_(2)CH_(2)CH_(3))underset(|)(CH)(CH_(2))_(4)CH_(3) (ix) CH_(3)CH_(2)CH_(2)CH_(2)-overset(H_(3)C)overset(|)(C )=overset(CH_(2)CH_(3))overset(|)(C(CH_(2))_(3)CH_(3) (x) (xi) (xii) (xiii) (xiv) Tetramethylethlene (xv) (xvi) Strategy: Select the longest possible continuous carbon chain or ring containing the largest number of double bonds and carrying the maximum number of side chains. Change the suffix of the parent alkane from -ane to -ene.The parent chain is numbered from the end closer to C = C, whoese position is indicated by assigning the lower possible number to the first doubly bonded C. Subsitituents are designated in exactly the same way as done for branched alkanes. |
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Answer» Solution :(i) `3`-Methylbut- `1`-ene (ii) `2, 8`-Dimethyldeca- `3,6`-diene. (iii) OCTA- `1,3,5,7`-tetraene (iv) `2-(1`-Prophyl) pent -`1`-ene (v) `4`-Enthyl-`2, 6`-dimethyldec-`4`-ene (vi) `3-n`-Prophylpenta-`1, 4`-diene (vii) `4`-methylpent-`1`-ene (viii) `3`-prophyloct-`1`ene (ix) `5`-ETHYL-`6`-methyldec-`5`-ene (x) `2,3`-Dimethylhept-`2`-ene (xi) trans-Hept-`3`-ene (xii) `1,3`-Dimethylcyclohexene (xiii) `3`-Prophylhept-`1`-ene (xiv) `(CH_(3))_(2)C = C(CH_(3))_(2), 2,3`-Dimethylbut-`2`-ene (xv)`4`-Ethyl-`2`-methylhex-`1`-ene (xvi) `3,5`-Dimethylcyclohexene |
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