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Give the products formed on reductive ozonolysis with LAH and oxidative ozonolysis with H_(2)O_(2), from the compounds in question. |
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Answer» SOLUTION :In reductive ozonolysis with `LAH` or `NaBH_(4)`, convert aldehyde and ketone into ALCOHOL and in oxidative ozonolysis with `H_(2)O_(2)` (or the reagent given in the chapter), the ketone remains unchanged and CONVERTES aldehyde to acid. `a.i. ` Reductive ozonolysis with `LAH`.  `ii.`Oxidative ozonolysis, same answer  `b.i. ` Reductive ozonolysis with `LAH`.  `ii.` Oxadative ozonolysis.  `c.i. `Reductive ozonolysis with `LAH`.  `ii.` Oxidative ozonolysis.  `d.i.` Reductive ozonolysis with `LAH`.  `ii.` Oxidative ozonolysis.  `e. i.`Reductive ozonolysis with `LAH`.  `ii.` Oxidative ozonolysis.  `f.i.` Reductive ozonolysis with `LAH`.  `ii.` Oxidative ozonolysis.  `g. i.` Reductive ozonolysis with `LAH`.  Three stereoisomers are possible. Chiral `C` ATOM `=2` Terminal group same. `2^(n-1)=2^(2-1)=2^(1)=` Optically active isomers `(` paire of enantiomers `)` `2^((n-2)//2)=2^(0)=1=`MESO `(` opticaly inactive `)` `ii.` Oxidative ozonolysis.  
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