Given`^^^""^(@)=((1)/(3)Al^(3+))=63 cm^(2)//Omega` mol and `^^^ ""^(@)((1)/(2)SO_(4)^(2-))=80 cm^(2)//Omega mol`. The value of `^^^ ""^(@) Al_(2)(SO_(4))_(3)` would beA. `143 Omega^(-1) cm^(2) mol^(-1)`B. `206 Omega^(-1) cm^(2) mol^(-1)`C. `286 Omega^(-1) cm^(2) mol^(-1)`D. `858 Omega^(-1) cm^(2) mol^(-1)`

Given`^^^""^(@)=((1)/(3)Al^(3+))=63 cm^(2)//Omega` mol and `^^^ ""^(@)

1.	Given`^^^""^(@)=((1)/(3)Al^(3+))=63 cm^(2)//Omega` mol and `^^^ ""^(@)((1)/(2)SO_(4)^(2-))=80 cm^(2)//Omega mol`. The value of `^^^ ""^(@) Al_(2)(SO_(4))_(3)` would beA. `143 Omega^(-1) cm^(2) mol^(-1)`B. `206 Omega^(-1) cm^(2) mol^(-1)`C. `286 Omega^(-1) cm^(2) mol^(-1)`D. `858 Omega^(-1) cm^(2) mol^(-1)`
Answer» Correct Answer - D `Lambda_((Al^(3+))^(@) = 3 Lambda_(((1)/(3) Al^(3+)))` =` 3 xx 63 = 189 Omega^(-1) cm^(2) mol^(-1)` . `Lambda^(@) (SO_(4))^(2-) = 2 Lambda^(@) ((1)/(2) SO_(4)^(2-))` `= 2 xx 80 = 160 Omega^(-1) cm^(2) mol^(-1)` . `Lambda^(@) [Al_(2) (SO_(4))_(3)] = 2Lambda^(@) (Al^(3+) ) + 3 Lambda^(@) (SO_(4)^(2-))` `2 xx 189 +3 xx 160 = 858 Omega^(-1) cm^(2) mol^(-1)` .

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