1.

Given A(2, 3), B(5, 4), C(6, 7), D(3, 6). Find the lengths AB, BC, CD, AD.

Answer»

AB = \(\sqrt{(5-2)^2+(4-3)^2}\)

\(\sqrt{3^2+1^2}\) = \(\sqrt{9+1}=\sqrt{10}\)

BC = \(\sqrt{(6-5)^2+(7-4)^2}=\sqrt{10}\)

CD = \(\sqrt{(5-6)^2+(6-7)^2}=\sqrt{10}\)

AD = \(\sqrt{(3-2)^2+(6-3)^2}\)

\(\sqrt{1^2+3^2}=\sqrt{1+9}=\sqrt{10}\)



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