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Given a number of capacitors labelled as `C,V`. Find the minimum number of capacitors needed to get an arrangement equivalent to `C_(net),V_(net)`.A. `n=(C_("net"))/(C) xx(V_("net")^(2))/(V^(2))`B. `n=(C)/(C_("net"))xx(V^(2))/(V_("net")^(2))`C. `n=(C)/(C_("net"))xx(V)/(V_("net"))`D. `n=(C_("net"))/(C)xx(V_("net"))/(V)` |
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Answer» Correct Answer - A `F=(sigma Q)/(2 epsilon_(0))=(Q^(2))/(2 epsilon_(0)A)`. |
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