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Given a12=37,d=3,find d and s13 |
| Answer» Correct Question:\xa0In an APGiven a12\xa0= 37, d = 3, find ‘a’ and S12.Here, a12\xa0= 37, d= 3We know that, an\xa0= a + (n - 1)d\xa0a12\xa0= a + (12 - 1) x 3\xa037 = a + 11 x 3\xa0a = 37 - 33 = 4And, \xa0Similarly you can find S13, put n as 13 in Sn formula. | |