Given below are marks (out of 100) of 10 students in an examination . Calculate first and third quartiles. 90,64,79,33,85,59,60,70,40,95

Given below are marks (out of 100) of 10 students in an examination .

1.	Given below are marks (out of 100) of 10 students in an examination . Calculate first and third quartiles. 90,64,79,33,85,59,60,70,40,95
Answer» Solution :Arranged in assending order of MAGNITUDE , the ITEMS are `Q_(1)=(N+1)/(4)`th ITEM `=(10+1)/(4)` th item =`(11)/(4)` th item =2.75 th item Value of 2nd item=40 mValue of 3rd item=59 Difference =59-40=19 `Q_(1)=40+(0.75xx19)=40+14.25=54.25` marks `Q_(3)=(3(N+1))/(4)`th item=`(3(10+1))/(4)` th item `=(33)/(4)` th item=8.25 th item. Value of 8th item=85 Value of 9TH item=90 Difference =90-85=5 ` Q_(3)=85+(.25xx5)=85+1.25=86.25` marks