Given below are two quantities named A and B. Based on the given infor

1.	Given below are two quantities named A and B. Based on the given information, you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answers.Quantity A: A boat goes 8 km upstream and comes back in 6 hours. Speed of the current is 1 km/hr then find the time taken by the boat to travel the same distance in still water. Quantity B: 2 hours1. Quantity A > Quantity B2. Quantity A < Quantity B3. Quantity A ≥ Quantity B4. Quantity A ≤ Quantity B5. Quantity A = Quantity B or No relation.
Answer» Correct Answer - Option 1 : Quantity A > Quantity B Quantity A: Let the speed of boat in still water be B km/hr According to the given statement, boat goes 8 km upstream and comes back in 6 hours and speed of the current is 1 km/hr ⇒ {8/(B + 1)} + {8/(B - 1)} = 6 ⇒ 16B = 6B² - 6 ⇒ 6B² - 18B + 2B - 6 = 0 ⇒ 6B(B - 3) + 2(B - 3) = 0 ⇒ (B - 3)(6B + 2) = 0 ⇒ B = 3 km/hr and -2/6 km/hr ⇒ Speed of boat in still water = 3 km/hr ⇒ Time taken to cover the distance in still water = 8/3 = 2 hours 40 minutes Quantity B: 2 hours ∴ Quantity A > Quantity B

Given below are two quantities named A and B. Based on the given information, you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answers.Quantity A: A boat goes 8 km upstream and comes back in 6 hours. Speed of the current is 1 km/hr then find the time taken by the boat to travel the same distance in still water. Quantity B: 2 hours1. Quantity A > Quantity B2. Quantity A < Quantity B3. Quantity A ≥ Quantity B4. Quantity A ≤ Quantity B5. Quantity A = Quantity B or No relation.

Answer» Correct Answer - Option 1 : Quantity A > Quantity B

Quantity A:

Let the speed of boat in still water be B km/hr

According to the given statement, boat goes 8 km upstream and comes back in 6 hours and speed of the current is 1 km/hr

⇒ {8/(B + 1)} + {8/(B - 1)} = 6

⇒ 16B = 6B² - 6

⇒ 6B² - 18B + 2B - 6 = 0

⇒ 6B(B - 3) + 2(B - 3) = 0

⇒ (B - 3)(6B + 2) = 0

⇒ B = 3 km/hr and -2/6 km/hr

⇒ Speed of boat in still water = 3 km/hr

⇒ Time taken to cover the distance in still water = 8/3 = 2 hours 40 minutes

Quantity B:

2 hours

∴ Quantity A > Quantity B