1.

Given: C + 2S to CS_(2), DeltaH = 117 kJ C + O_(2) to CO_(2), DeltaH = -393 kJ S + O_(2) to SO_(2) DeltaH = -297 kJ The heat of combustion of CS_(2) to form CO_(2) and SO_(2) is

Answer»

`-1104 kJ"mol"^(-1)`
`1104 kJ"mol"^(-1)`
`+807 kJ"mol"^(-1)`
`-807 kJ"mol"^(-1)`

Solution :The required equation is
`CS_(2) + 3O_(2) to CO_(2)+ 2SO_(2)`
(i) ` C + 2S to CS_(2)DeltaH = 117 kJ`
(ii) `C + O_(2) to CO_(2) DeltaH = -393 kJ`
(iii) `S + O_(2) to SO_(2)DeltaH = -297 kJ`
Multiply eqn.(iii) by 2 and subtract eqn(i) from it
(iv) `CS_(2) + 2O_(2) to C _ 2SO_(2)DeltaH = -711 kJ`
Add eqn.(ii) to eqn(iv)
`CS_(2) + 3O_(2) to CO_(2)+2SO_(2)DeltaH = -1104 kJ`.


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