Given ΔABC ~ ΔPQR, if \(\frac{AB}{PQ}\) = \(\frac{1}{3}\), then \(\f

1.	Given ΔABC ~ ΔPQR, if \(\frac{AB}{PQ}\) = \(\frac{1}{3}\), then \(\frac{ar(ΔABC)}{ar(ΔPQR)}\) = .............
Answer» \(\frac{ar(ΔABC)}{ar(ΔPQR)}\) = \(\frac{1}{9}\) \(\frac{ar(ΔABC)}{ar(ΔPQR)}\) = \(\frac{(AB)^2}{(PQ)^2}\) = \((\frac{1}{3})^2\) = \(\frac{1}{9}\)

Given ΔABC ~ ΔPQR, if \(\frac{AB}{PQ}\) = \(\frac{1}{3}\), then \(\frac{ar(ΔABC)}{ar(ΔPQR)}\) = .............

Answer»

\(\frac{ar(ΔABC)}{ar(ΔPQR)}\) = \(\frac{1}{9}\)

\(\frac{ar(ΔABC)}{ar(ΔPQR)}\) = \(\frac{(AB)^2}{(PQ)^2}\) = \((\frac{1}{3})^2\) = \(\frac{1}{9}\)

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Given ΔABC ~ ΔPQR, if \(\frac{AB}{PQ}\) = \(\frac{1}{3}\), then \(\frac{ar(ΔABC)}{ar(ΔPQR)}\) = .............

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