Given,`{:(E_(Fe^(3+) //Fe)^o + 3e Cr E^o =- 0.036 V),(E_(Fe^(3+) //Fe)^o =- 0.439 V):}` The value of standard electrode ptoential for the charge,A. `0.770V`B. `-0.27V`C. `-0.072V`D. `0.385V`

Given,`{:(E_(Fe^(3+) //Fe)^o + 3e Cr E^o =- 0.036 V),(E_(Fe^(3+) //Fe)

1.	Given,`{:(E_(Fe^(3+) //Fe)^o + 3e Cr E^o =- 0.036 V),(E_(Fe^(3+) //Fe)^o =- 0.439 V):}` The value of standard electrode ptoential for the charge,A. `0.770V`B. `-0.27V`C. `-0.072V`D. `0.385V`
Answer» Correct Answer - A `Fe^(3+) +3e rarr Fe` ...(1) `E^(@) = 0.036V` `:. DeltaG_(1)^(@) = nFE^(@)` `=- 3 xx F(-0.036V)` `= 0.108F` Also, `Fe^(2+) +2e rarr Fe` ..(2) `E^(@) =- 0.439V` `:. DeltaG_(2)^(@) = nFE^(@)` `=- 2 xx F(0.439)` `=08.78 F` For `Fe^(3+) (aq) +e^(-) rarr Fe^(2+) (aq)` ..(3) `:.` Assume `E^(@) = xV` eq.(1)-eq.(2) produces eq.(3) `:. DeltaG^(@) = DeltaG_(1)^(@) - DeltaG_(2)^(@)` `-1 xx F xx x = 0.108 F - 0.878F` `- x =- 0.77` `x = 0.77V`

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Given,`{:(E_(Fe^(3+) //Fe)^o + 3e Cr E^o =- 0.036 V),(E_(Fe^(3+) //Fe)^o =- 0.439 V):}` The value of standard electrode ptoential for the charge,A. `0.770V`B. `-0.27V`C. `-0.072V`D. `0.385V`

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