Given ∫ex(tanx + 1) secxdx = exf(x) + c.

1.	Given ∫ex(tanx + 1) secxdx = exf(x) + c.
Answer» ∫e^x (secx + sec x tanx)dx By the property ∫e^x(f (x) + f '(x))dx = e^xf(x) + c So, I = e^xsecx + c So, f(x) = secx

Answer»

∫e^x (secx + sec x tanx)dx

By the property

∫e^x(f (x) + f '(x))dx = e^xf(x) + c

So, I = e^xsecx + c

So, f(x) = secx

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Given ∫ex(tanx + 1) secxdx = exf(x) + c.

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