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Given `F = (a//t) + bt^2` where F denotes force and t time. The diamensions of a and b are respectively :A. `[MLT^(-1)] and [MLT^(-4)]`B. `[LT^(-1)] and [T^(-2)]`C. `[T] and [T^(-2)]`D. `[LT^(-2)] and [T^(-2)]` |
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Answer» Correct Answer - (a) Here a//t and `bt^2` both should represent the force, `:. F = (a)/(t)` `:. a = Fxx t = MLT^(-2)xxT = MLT^O(-4)` `Also, F =bt^2,` `:. b = (F)/(t^2), i.e., b= (MLT^(-2))/(T^2) = MLT^(-4)` `b =MLT^(-4)` |
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