Given F = A’B + (C’ + E)(D + F’), use de Morgan’s theorem to f

1.	Given F = A’B + (C’ + E)(D + F’), use de Morgan’s theorem to find F’.(a) ACE’ + BCE’ + D’F(b) (A + B’)(CE’ + D’F)(c) A + B + CE’D’F(d) ACE’ + AD’F + B’CE’ + B’CE’ + B’D’F(e) NA
Answer» A’B + (C’ + E)(D + F’) = (A’B)’ + ((C’ + E)(D + F’))’ = (AB’) + (C’ + E)’(D + F’)’ = (AB’) + (C + E’)(D’ + F) = (A + B’)(CE’ + D’F) So , F’ = (A + B’)(CE’ + D’F)

Given F = A’B + (C’ + E)(D + F’), use de Morgan’s theorem to find F’.(a) ACE’ + BCE’ + D’F(b) (A + B’)(CE’ + D’F)(c) A + B + CE’D’F(d) ACE’ + AD’F + B’CE’ + B’CE’ + B’D’F(e) NA

Answer»

A’B + (C’ + E)(D + F’)

= (A’B)’ + ((C’ + E)(D + F’))’

= (AB’) + (C’ + E)’(D + F’)’

= (AB’) + (C + E’)(D’ + F)

= (A + B’)(CE’ + D’F)

So , F’ = (A + B’)(CE’ + D’F)

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Given F = A’B + (C’ + E)(D + F’), use de Morgan’s theorem to find F’.(a) ACE’ + BCE’ + D’F(b) (A + B’)(CE’ + D’F)(c) A + B + CE’D’F(d) ACE’ + AD’F + B’CE’ + B’CE’ + B’D’F(e) NA

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