Given →F=(xy2)^i+(x2y)^jN. The work done by →F when a particle is

1.	Given →F=(xy2)^i+(x2y)^jN. The work done by →F when a particle is taken along the semicircular path OAB where the coordinates of B are (4,0) is
Answer» Given $\to F = (x y^{2})^i + (x^{2} y)^j N$ . The work done by $\to F$ when a particle is taken along the semicircular path OAB where the coordinates of B are (4,0) is

Given →F=(xy2)^i+(x2y)^jN. The work done by →F when a particle is taken along the semicircular path OAB where the coordinates of B are (4,0) is

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Given $\to F = (x y^{2})^i + (x^{2} y)^j N$ . The work done by $\to F$ when a particle is taken along the semicircular path OAB where the coordinates of B are (4,0) is

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Given →F=(xy2)^i+(x2y)^jN. The work done by →F when a particle is taken along the semicircular path OAB where the coordinates of B are (4,0) is

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