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given figure, ZB < LA and LD > LC, then B(a) AD > BC(b) AD BC(c) AD <BC(d) AD 2BC6. In the640 |
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Answer» In ∆ OAB, angle B < angle A So, AO < BO ....(1) In ∆ ODC, angle C < angle D OD < OC ....(2) Adding (1) and (2) AO + OD < BO + OC AD < BC c) is correct |
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