1.

Given, for air c_(upsilon) =0.162 cal g^(-1) K^(-1) and density at NTP is 0.001293 g cm^(-3) What is the value of c_p ?

Answer»

`0.123 CAL g^(-1) K^(-1)`
`0.23 cal^(-1) g^(-1) K^(-1)`
`0.246 cal g^(-1) K^(-1)`
`0.46 cal^(-1) g^(-1)`

Answer :B


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