InterviewSolution
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InterviewSolution
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Given : force `= (alpha)/("density" + beta^3).` What are the dimensions of `alpha, beta ?`A. `M L^(-2) T^(-2), ML^(-1//3)`B. `M^2 L^4 T^(-2), M^(1//3) L^(-1)`C. `M^2 L^(-2) T^(-2), M^(1//3) L^(-1)`D. `M^2 L^(-2), M L^(-3)` |
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Answer» Correct Answer - (c ) `beta^3 = "density" = M^1 L^(-3) = beta =M^(1//3) L^(-1)` Also, `alpha = "force" xx "density"` `=MLT^(-2)xx M^1 L^(-3) = [M^2 L^9-2)T^(-2)]` |
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