InterviewSolution
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InterviewSolution
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Given is the graph between `(PV)/T` and P for 1 gm of oxygen gas at two different temperatures `T_(1) and T_(2)` Fig. Given, density of oxygen `= 1.427 kg m^(-3)`. The value of `(PV)//(T)` at the point A and the relation between `T_(1) and T_(2)` are respectively : A. `0.256 JK^(-1) and T_(1) lt T(2)`B. `8.314 mol^(-1) K^(-1) and T_(1) gt T(2)`C. `0.256 JK^(-1) and T_(1) gt T(2)`D. `4.28 JK^(-1) and T_(1) lt T(2)` |
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Answer» Correct Answer - C `PV = nRT = m/M RT` Where m = mass of the gas and `m/M = n =` number of moles `(PV)/(T) = nR = a` constant for all value of P. That is why, ideally it is a straight line. `:. (PV)/T = (1 gm)/(32 gm) xx 8.31 J "mole"^(-1) K^(-1)` `= 0.256 JK^(-1)`. Also, `T_(1) gt T_(2)`. |
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