Given items as {value,weight} pairs {{40,20},{30,10},{20,5}}. The capacity of knapsack=20. Find the maximum value output assuming items to be divisible.(a) 60(b) 80(c) 100(d) 40The question was posed to me in an internship interview.I want to ask this question from Greedy Algorithms in division Greedy Algorithms of Data Structures & Algorithms II

Given items as {value,weight} pairs {{40,20},{30,10},{20,5}}. The capa

1.	Given items as {value,weight} pairs {{40,20},{30,10},{20,5}}. The capacity of knapsack=20. Find the maximum value output assuming items to be divisible.(a) 60(b) 80(c) 100(d) 40The question was posed to me in an internship interview.I want to ask this question from Greedy Algorithms in division Greedy Algorithms of Data Structures & Algorithms II
Answer» CORRECT answer is (a) 60 Easiest explanation - The value/weight ratio are-{2,3,4}. So we include the SECOND and THIRD items wholly into the knapsack. This LEAVES only 5 units of volume for the first item. So we include the first item partially. Final value = 20+30+(40/4)=60.

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