Given `l//a=0.5 cm^(-1), R= 50 "ohm", N= 1.0.` The equivalent conductance of the electrolytic cell is .A. 10 `ohm^(-1)cm^(2)gmeq^(-1)`B. 20 `ohm^(-1)cm^(2)gmeq^(-1)`C. 300 ohm S `cm^(2)eq^(-1)`D. 135.9S `cm^(2)eq^(-1)`

Given `l//a=0.5 cm^(-1), R= 50 "ohm", N= 1.0.` The equivalent conducta

1.	Given `l//a=0.5 cm^(-1), R= 50 "ohm", N= 1.0.` The equivalent conductance of the electrolytic cell is .A. 10 `ohm^(-1)cm^(2)gmeq^(-1)`B. 20 `ohm^(-1)cm^(2)gmeq^(-1)`C. 300 ohm S `cm^(2)eq^(-1)`D. 135.9S `cm^(2)eq^(-1)`
Answer» Correct Answer - A `1//a=0.5cm^(-1),R=50ohm` `p=(Ra)/(I)=(50)/(0.5)=100` `wedge=kxx(1000)/(N)=(1)/(p)xx(1000)/(N)=(1)/(100)0xx(1000)/(1)` `=10ohm^(-1)cm^(2)gm" "eq^(-1)`.

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Given `l//a=0.5 cm^(-1), R= 50 "ohm", N= 1.0.` The equivalent conductance of the electrolytic cell is .A. 10 `ohm^(-1)cm^(2)gmeq^(-1)`B. 20 `ohm^(-1)cm^(2)gmeq^(-1)`C. 300 ohm S `cm^(2)eq^(-1)`D. 135.9S `cm^(2)eq^(-1)`

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