Given log 2=30103, log 3=0.47712, log find the value of\log _{6} 6, \l – InterviewSolution

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1.	Given log 2=30103, log 3=0.47712, log find the value of\log _{6} 6, \log 1.5, \log \frac{x}{25}
Answer» log6=log(2×3)=log2+log3=0.30103+0.47712 =0.77815log1.5=log(3/2)=log3-log2=0.47712-0.30103 =0.17609log(1/2.5)=log(2/5)=log2-log5 =log2-log(10/2)=log2-log10+log2 =2log2-log10=2×0.30103-1 =-0.39794

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