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Given mass of the moon is 1/81 of the mass of the earth and corresponding radius is 1/4 of the earth. If escape velocity on the earth surface is 11.2 km / s , the value of same on the surface of the moon isA. 0.14 km/sB. 0.5 km/sC. 2.5 km/sD. 5 km/s |
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Answer» Correct Answer - C On earth `v_e=sqrt((2GM)/R)` =11.2 km/s On moon `v_m=sqrt((2GMxx4)/(81xxR))=2/9sqrt((2GM)/R)` `=2/9xx11.2` =2.5 km/s |
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